We explain to you what the Law of Universal Gravitation is, how is its formula and its statement. In addition, examples of the use of its formula.
The Law of Universal Gravitation is one of the physical laws formulated by Isaac Newton in his book Philosophiae Naturalis Principia Mathematica of 1687. It describes the gravitational interaction between bodies endowed with mass , and establishes a proportional relationship of the force with which those bodies attract the each other.
To formulate this law, Newton deduced that the force with which two masses attract is proportional to the product of their masses divided by distance that separates them squared. These deductions are the result of empirical verification by observation, as well as the mathematical genius of the English scientist.
Hence, by increasing the distance that separates two bodies, this law acts approximately, as if the entire mass of both bodies is concentrated in its center of gravity . That is, the closer and more massive two bodies are, the more intensely they will attract . Like other Newtonian laws, it represented a leap forward in the scientific calculation of the time.
However, today we know that, from a certain amount of mass, this law loses its validity
(that is, in the case of supermassive objects), then passing the witness to the General Relativity Law formulated in 1915 by Albert Einstein. However, the Law of Universal Gravitation is still useful to understand most of the gravitational phenomena of the Solar System.The formal statement of this Newtonian law says that
” The force with which two objects are attracted is proportional to the product of their masses and inversely proportional to the square of the distance that separates them .”
This means that any two bodies are attracted with a greater or lesser force depending on their mass being greater or lesser, and also depending on the distance between them.
The fundamental formula of the Law of Universal Gravitation is the following:
Where:
If the attractive forces of each body (F 1 and F 2 ) are calculated , there will be two equal forces in modulus and in the opposite direction, and instead of being canceled, they are combined. This requires a vector formula:
F 12 = -G. (m 1 .m 2 ) / ǁr 2 -r 1 ǁ 2 . ȗ 12
Where ȗ 12 is the unit vector that can be drawn from the center of gravity of one object to the other.
Let’s solve a couple of exercises as an example of the application of this formula.
Simply by applying the formula:
F = G. (m 1 .m 2 ) / r 2
What will it be: F = (6.67 × 10 -11 Nm 2 / kg 2 ). (800 kg. 500 kg) / (3) 2
And then: F = 2,964 x 10 -6 N.
Starting from the same formula
F = G. (m 1 .m 2 ) / r 2
We will clear the distance, staying that r 2 = G. (m 1 .m 2 ) / F
Or what is the same: r = √ (G. [m 1 .m 2 ]) / F
That is: r = √ (6.67 × 10 -11 Nm 2 / kg 2. 1kg x 1kg) / 1N
The result is that r = 8.16 x 10 -6 meters.
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